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BOSTON. |
237 |
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10 are 12, which multiplied by 2, as stated in the table, make 24, that is two fish to be paid, the remainder not being taken notice of.
But if the player, or player and partner, do not get their tricks, then the number they are deficient, added both to what they undertook, and the honours they held, is to be multiplied by the number found in the table, and divided by 10, to shew the fish to be paid by them to their antagonists : for instance, when they undertake five and three tricks, having two by honours, the trump in a common suit, suppose they get only six tricks, then 6 substracted from 8 leave 2, which added to 8 the number they undertook, and 2 the honours they held, make 12 ; this multiplied by 1, and divided by 10, gives one fish. If they undertake five and three tricks, having two by honours, the trump in second preference, should they get but 7, then 1 they are deficient, added to 8 they undertook, and 2 honours, make 11 : this multiplied by 2, the number in the table, makes 22, which divided by 10, leaves 2, the fish to be paid. Should they undertake six and four tricks, having four honours, the trump in the first preference ; suppose they get but eight tricks, 8 from 10, leave 2, which, added to the 10 they undertook, and 4 honours, form 16 ; that multiplied by 8, as in the table, make 128 ; then 130 divided by 10, gives 13 fish to be paid by them.
Should the player and partner each fail to get their proposed number of tricks, then the fish to be paid by them is to be defrayed in equal proportions between them ; exactly the reverse of what would have been done had they been successful. But should one get his number of tricks and the other fail, then the unsuccessful person bears the whole of the loss, and when the player is alone, |
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